2x^2+4x+8=2x^2+4x+8

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Solution for 2x^2+4x+8=2x^2+4x+8 equation: 


Simplifying
2x2 + 4x + 8 = 2x2 + 4x + 8

Reorder the terms:
8 + 4x + 2x2 = 2x2 + 4x + 8

Reorder the terms:
8 + 4x + 2x2 = 8 + 4x + 2x2

Add '-8' to each side of the equation.
8 + 4x + -8 + 2x2 = 8 + 4x + -8 + 2x2

Reorder the terms:
8 + -8 + 4x + 2x2 = 8 + 4x + -8 + 2x2

Combine like terms: 8 + -8 = 0
0 + 4x + 2x2 = 8 + 4x + -8 + 2x2
4x + 2x2 = 8 + 4x + -8 + 2x2

Reorder the terms:
4x + 2x2 = 8 + -8 + 4x + 2x2

Combine like terms: 8 + -8 = 0
4x + 2x2 = 0 + 4x + 2x2
4x + 2x2 = 4x + 2x2

Add '-4x' to each side of the equation.
4x + -4x + 2x2 = 4x + -4x + 2x2

Combine like terms: 4x + -4x = 0
0 + 2x2 = 4x + -4x + 2x2
2x2 = 4x + -4x + 2x2

Combine like terms: 4x + -4x = 0
2x2 = 0 + 2x2
2x2 = 2x2

Add '-2x2' to each side of the equation.
2x2 + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
0 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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